2022 day 3 part 1 (bash)

This commit is contained in:
2022-12-07 17:31:29 +01:00
parent 01cdce6608
commit d1026e8f59
6 changed files with 675 additions and 0 deletions

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2022/day03/Makefile Normal file
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# AOC daily Makefile - GNU make only.
#
# Copyright (C) 2021-2022 Bruno Raoult ("br")
# Licensed under the GNU General Public License v3.0 or later.
# Some rights reserved. See COPYING.
#
# You should have received a copy of the GNU General Public License along with this
# program. If not, see <https://www.gnu.org/licenses/gpl-3.0-standalone.html>.
#
# SPDX-License-Identifier: GPL-3.0-or-later <https://spdx.org/licenses/GPL-3.0-or-later.html>
#
INPUT := input/input.txt
SHELL := /bin/bash
CC := gcc
BEAR := bear
CCLSFILE:= compile_commands.json
LIB := aoc_$(shell uname -m)
INCDIR := ../include
LIBDIR := ../lib
LDFLAGS := -L$(LIBDIR)
#LDLIB := -l$(LIB) -lm
LDLIB := -l$(LIB)
export LD_LIBRARY_PATH = $(LIBDIR)
CFLAGS += -std=gnu11
CFLAGS += -O2
CFLAGS += -g
# for gprof
# CFLAGS += -pg
CFLAGS += -Wall
CFLAGS += -Wextra
CFLAGS += -march=native
# Next one may be useful for valgrind (some invalid instructions)
# CFLAGS += -mno-tbm
CFLAGS += -Wmissing-declarations
CFLAGS += -Wno-unused-result
CFLAGS += -DDEBUG_DEBUG # activate general debug (debug.c)
CFLAGS += -DDEBUG_POOL # memory pools management
VALGRIND := valgrind
VALGRINDFLAGS := --leak-check=full --show-leak-kinds=all --track-origins=yes \
--sigill-diagnostics=yes --quiet --show-error-list=yes
TIME := \time -f "\ttime: %E real, %U user, %S sys\n\tcontext-switch:\t%c+%w, page-faults: %F+%R\n"
export PATH := .:$(PATH)
.PHONY: clean all compile assembly memcheck memcheck1 memcheck2 part1 part2 ccls bear org
all: README.org ccls part1 part2
memcheck: memcheck1 memcheck2
memcheck1: aoc-c
@$(VALGRIND) $(VALGRINDFLAGS) aoc-c -p 1 < $(INPUT)
memcheck2: aoc-c
@$(VALGRIND) $(VALGRINDFLAGS) aoc-c -p 2 < $(INPUT)
@#@valgrind -s --track-origins=yes aoc-c -p 2 < $(INPUT)
compile: aoc-c
cpp: aoc-c.i
assembly: aoc-c.s
part1: aoc-c
@$(TIME) aoc.bash -p 1 < $(INPUT) 2>&1
@$(TIME) aoc-c -p 1 < $(INPUT)
part2: aoc-c
@$(TIME) aoc.bash -p 2 < $(INPUT) 2>&1
@$(TIME) aoc-c -p 2 < $(INPUT)
ccls: $(CCLSFILE)
clean:
@rm -f aoc-c core* vgcore* gmon.out aoc-c.s aoc-c.i README.html compile_commands.json
aoc-c: aoc-c.c common.c
@echo compiling $<
$(CC) $(CFLAGS) $(LDFLAGS) -I $(INCDIR) $^ $(LDLIB) -o $@
# generate pre-processed file (.i) and assembler (.s)
%.i: %.c
@echo generating $@
@$(CC) -E $(CFLAGS) -I $(INCDIR) $< -o $@
%.s: %.c
@echo generating $@
@$(CC) -S -fverbose-asm $(CFLAGS) -I $(INCDIR) $< -o $@
# generate README.org from README.html (must cleanup !)
org: README.org
%.org: %.html
@echo generating $@. Cleanup before commit !
@pandoc $< -o $@
# generate compile_commands.json
$(CCLSFILE): aoc-c.c Makefile
$(BEAR) -- make clean compile
bear: clean
@touch .ccls-root
@$(BEAR) -- make compile

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2022/day03/README.org Normal file
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** --- Day 3: Rucksack Reorganization ---
One Elf has the important job of loading all of the
[[https://en.wikipedia.org/wiki/Rucksack][rucksacks]] with supplies for
the jungle journey. Unfortunately, that Elf didn't quite follow the
packing instructions, and so a few items now need to be rearranged.
Each rucksack has two large /compartments/. All items of a given type
are meant to go into exactly one of the two compartments. The Elf that
did the packing failed to follow this rule for exactly one item type per
rucksack.
The Elves have made a list of all of the items currently in each
rucksack (your puzzle input), but they need your help finding the
errors. Every item type is identified by a single lowercase or uppercase
letter (that is, =a= and =A= refer to different types of items).
The list of items for each rucksack is given as characters all on a
single line. A given rucksack always has the same number of items in
each of its two compartments, so the first half of the characters
represent items in the first compartment, while the second half of the
characters represent items in the second compartment.
For example, suppose you have the following list of contents from six
rucksacks:
#+begin_example
vJrwpWtwJgWrhcsFMMfFFhFp
jqHRNqRjqzjGDLGLrsFMfFZSrLrFZsSL
PmmdzqPrVvPwwTWBwg
wMqvLMZHhHMvwLHjbvcjnnSBnvTQFn
ttgJtRGJQctTZtZT
CrZsJsPPZsGzwwsLwLmpwMDw
#+end_example
- The first rucksack contains the items =vJrwpWtwJgWrhcsFMMfFFhFp=,
which means its first compartment contains the items =vJrwpWtwJgWr=,
while the second compartment contains the items =hcsFMMfFFhFp=. The
only item type that appears in both compartments is lowercase =p=.
- The second rucksack's compartments contain =jqHRNqRjqzjGDLGL= and
=rsFMfFZSrLrFZsSL=. The only item type that appears in both
compartments is uppercase =L=.
- The third rucksack's compartments contain =PmmdzqPrV= and =vPwwTWBwg=;
the only common item type is uppercase =P=.
- The fourth rucksack's compartments only share item type =v=.
- The fifth rucksack's compartments only share item type =t=.
- The sixth rucksack's compartments only share item type =s=.
To help prioritize item rearrangement, every item type can be converted
to a /priority/:
- Lowercase item types =a= through =z= have priorities 1 through 26.
- Uppercase item types =A= through =Z= have priorities 27 through 52.
In the above example, the priority of the item type that appears in both
compartments of each rucksack is 16 (=p=), 38 (=L=), 42 (=P=), 22 (=v=),
20 (=t=), and 19 (=s=); the sum of these is =157=.
Find the item type that appears in both compartments of each rucksack.
/What is the sum of the priorities of those item types?/
Your puzzle answer was =7878=.
The first half of this puzzle is complete! It provides one gold star: *
** --- Part Two ---
As you finish identifying the misplaced items, the Elves come to you
with another issue.
For safety, the Elves are divided into groups of three. Every Elf
carries a badge that identifies their group. For efficiency, within each
group of three Elves, the badge is the /only item type carried by all
three Elves/. That is, if a group's badge is item type =B=, then all
three Elves will have item type =B= somewhere in their rucksack, and at
most two of the Elves will be carrying any other item type.
The problem is that someone forgot to put this year's updated
authenticity sticker on the badges. All of the badges need to be pulled
out of the rucksacks so the new authenticity stickers can be attached.
Additionally, nobody wrote down which item type corresponds to each
group's badges. The only way to tell which item type is the right one is
by finding the one item type that is /common between all three Elves/ in
each group.
Every set of three lines in your list corresponds to a single group, but
each group can have a different badge item type. So, in the above
example, the first group's rucksacks are the first three lines:
#+begin_example
vJrwpWtwJgWrhcsFMMfFFhFp
jqHRNqRjqzjGDLGLrsFMfFZSrLrFZsSL
PmmdzqPrVvPwwTWBwg
#+end_example
And the second group's rucksacks are the next three lines:
#+begin_example
wMqvLMZHhHMvwLHjbvcjnnSBnvTQFn
ttgJtRGJQctTZtZT
CrZsJsPPZsGzwwsLwLmpwMDw
#+end_example
In the first group, the only item type that appears in all three
rucksacks is lowercase =r=; this must be their badges. In the second
group, their badge item type must be =Z=.
Priorities for these items must still be found to organize the sticker
attachment efforts: here, they are 18 (=r=) for the first group and 52
(=Z=) for the second group. The sum of these is =70=.
Find the item type that corresponds to the badges of each three-Elf
group. /What is the sum of the priorities of those item types?/
Answer:
Although it hasn't changed, you can still [[file:3/input][get your
puzzle input]].
You can also [Shareon
[[https://twitter.com/intent/tweet?text=I%27ve+completed+Part+One+of+%22Rucksack+Reorganization%22+%2D+Day+3+%2D+Advent+of+Code+2022&url=https%3A%2F%2Fadventofcode%2Ecom%2F2022%2Fday%2F3&related=ericwastl&hashtags=AdventOfCode][Twitter]]
[[javascript:void(0);][Mastodon]]] this puzzle.

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#!/usr/bin/env bash
#
# aoc.bash: Advent of Code 2022, day 2
#
# Copyright (C) 2022 Bruno Raoult ("br")
# Licensed under the GNU General Public License v3.0 or later.
# Some rights reserved. See COPYING.
#
# You should have received a copy of the GNU General Public License along with this
# program. If not, see <https://www.gnu.org/licenses/gpl-3.0-standalone.html>.
#
# SPDX-License-Identifier: GPL-3.0-or-later <https://spdx.org/licenses/GPL-3.0-or-later.html>
. common.bash
export LANG=C
declare -a tot=(1 2)
# get priority value for an item
# $1: character
prio() {
local -n _val="$1"
local _char="$2"
printf -v _val "%d" "'$_char"
if [[ $_char > "Z" ]]; then # a-z
((_val += (1 - 97) ))
else # A-Z
((_val += (27 - 65) ))
fi
}
parse() {
local input half1 half2 result=""
local -i len half i j=1 prio part1=0 line=1
while read -r input; do
(( len = ${#input}, half = len/2 ))
half1="${input:0:half}"
half2="${input:half}"
result=""
#printf "[%d] l=%d h=%d [%s / %s]\n" "$line" "$len" "$half" "$half1" "$half2"
#c="${half1//[^${half2}]}"
#prio prio "${c:0:1}"
#(( part1 += prio ))
for ((i = 0; i < half; ++i)); do
c=${half1:$i:1}
if [[ $result != *$c* && $half2 == *$c* ]]; then
echo "found $c"
result=$result$c
prio prio "${c:0:1}"
(( part1 += prio ))
#printf "%d prio(%c)=%d tot=%d\n" "$line" "$c" "$prio" "$part1"
fi
done
((j++, line++))
echo
done
echo "result=$part1"
}
solve() {
res="${tot[$1]}"
}
main "$@"
exit 0

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#!/usr/bin/env bash
#
# common.bash: Advent of Code 2022, common bash functions
#
# Copyright (C) 2022 Bruno Raoult ("br")
# Licensed under the GNU General Public License v3.0 or later.
# Some rights reserved. See COPYING.
#
# You should have received a copy of the GNU General Public License along with this
# program. If not, see <https://www.gnu.org/licenses/gpl-3.0-standalone.html>.
#
# SPDX-License-Identifier: GPL-3.0-or-later <https://spdx.org/licenses/GPL-3.0-or-later.html>
# shellcheck disable=2034
export cmdname=${0##*/}
export debug=0
export res
shopt -s extglob
set -o noglob
usage() {
printf "usage: %s [-d DEBUG] [-p PART]\n" "$cmdname"
exit 1
}
checkargs() {
local part=1
while getopts p:d: todo; do
case "$todo" in
d)
if [[ "$OPTARG" =~ ^[[:digit:]+]$ ]]; then
debug="$OPTARG"
else
printf "%s: illegal [%s] debug level.\n" "$CMD" "$OPTARG"
exit 1
fi
;;
p)
if [[ "$OPTARG" =~ ^[12]$ ]]; then
part="$OPTARG"
else
printf "%s: illegal [%s] part.\n" "$CMD" "$OPTARG"
exit 1
fi
;;
*)
usage
;;
esac
done
# Now check remaining argument (backup directory)
shift $((OPTIND - 1))
(( $# > 1 )) && usage
return "$part"
}
main() {
local -i part
checkargs "$@"
part=$?
parse "$part"
solve "$part"
printf "%s: res=%s\n" "$cmdname" "$res"
}

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vJrwpWtwJgWrhcsFMMfFFhFp
jqHRNqRjqzjGDLGLrsFMfFZSrLrFZsSL
PmmdzqPrVvPwwTWBwg
wMqvLMZHhHMvwLHjbvcjnnSBnvTQFn
ttgJtRGJQctTZtZT
CrZsJsPPZsGzwwsLwLmpwMDw

300
2022/day03/input/input.txt Normal file
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