diff --git a/2022/day03/Makefile b/2022/day03/Makefile
new file mode 100644
index 0000000..e0add74
--- /dev/null
+++ b/2022/day03/Makefile
@@ -0,0 +1,111 @@
+# AOC daily Makefile - GNU make only.
+#
+# Copyright (C) 2021-2022 Bruno Raoult ("br")
+# Licensed under the GNU General Public License v3.0 or later.
+# Some rights reserved. See COPYING.
+#
+# You should have received a copy of the GNU General Public License along with this
+# program. If not, see <https://www.gnu.org/licenses/gpl-3.0-standalone.html>.
+#
+# SPDX-License-Identifier: GPL-3.0-or-later <https://spdx.org/licenses/GPL-3.0-or-later.html>
+#
+
+INPUT   := input/input.txt
+SHELL   := /bin/bash
+
+CC      := gcc
+BEAR    := bear
+CCLSFILE:= compile_commands.json
+
+LIB     := aoc_$(shell uname -m)
+INCDIR  := ../include
+LIBDIR  := ../lib
+LDFLAGS := -L$(LIBDIR)
+#LDLIB   := -l$(LIB) -lm
+LDLIB   := -l$(LIB)
+
+export LD_LIBRARY_PATH = $(LIBDIR)
+
+CFLAGS  += -std=gnu11
+CFLAGS  += -O2
+CFLAGS  += -g
+# for gprof
+# CFLAGS += -pg
+CFLAGS  += -Wall
+CFLAGS  += -Wextra
+CFLAGS  += -march=native
+# Next one may be useful for valgrind (some invalid instructions)
+# CFLAGS += -mno-tbm
+CFLAGS  += -Wmissing-declarations
+CFLAGS  += -Wno-unused-result
+
+CFLAGS  += -DDEBUG_DEBUG 	# activate general debug (debug.c)
+CFLAGS  += -DDEBUG_POOL		# memory pools management
+
+VALGRIND := valgrind
+VALGRINDFLAGS := --leak-check=full --show-leak-kinds=all --track-origins=yes \
+	--sigill-diagnostics=yes --quiet --show-error-list=yes
+
+
+TIME    := \time -f "\ttime: %E real, %U user, %S sys\n\tcontext-switch:\t%c+%w, page-faults: %F+%R\n"
+export PATH := .:$(PATH)
+
+.PHONY: clean all compile assembly memcheck memcheck1 memcheck2 part1 part2 ccls bear org
+
+all: README.org ccls part1 part2
+
+memcheck: memcheck1 memcheck2
+
+memcheck1: aoc-c
+	@$(VALGRIND) $(VALGRINDFLAGS) aoc-c -p 1 < $(INPUT)
+
+memcheck2: aoc-c
+	@$(VALGRIND) $(VALGRINDFLAGS) aoc-c -p 2 < $(INPUT)
+	@#@valgrind -s --track-origins=yes aoc-c -p 2 < $(INPUT)
+
+compile: aoc-c
+
+cpp: aoc-c.i
+
+assembly: aoc-c.s
+
+part1: aoc-c
+	@$(TIME) aoc.bash -p 1 < $(INPUT) 2>&1
+	@$(TIME) aoc-c -p 1 < $(INPUT)
+
+part2: aoc-c
+	@$(TIME) aoc.bash -p 2 < $(INPUT) 2>&1
+	@$(TIME) aoc-c -p 2 < $(INPUT)
+
+ccls: $(CCLSFILE)
+
+clean:
+	@rm -f aoc-c core* vgcore* gmon.out aoc-c.s aoc-c.i README.html compile_commands.json
+
+aoc-c: aoc-c.c common.c
+	@echo compiling $<
+	$(CC) $(CFLAGS) $(LDFLAGS) -I $(INCDIR) $^ $(LDLIB) -o $@
+
+# generate pre-processed file (.i) and assembler (.s)
+%.i: %.c
+	@echo generating $@
+	@$(CC) -E $(CFLAGS) -I $(INCDIR) $< -o $@
+
+%.s: %.c
+	@echo generating $@
+	@$(CC) -S -fverbose-asm $(CFLAGS) -I $(INCDIR) $< -o $@
+
+# generate README.org from README.html (must cleanup !)
+org: README.org
+
+%.org: %.html
+	@echo generating $@. Cleanup before commit !
+	@pandoc $< -o $@
+
+# generate compile_commands.json
+$(CCLSFILE): aoc-c.c Makefile
+	$(BEAR) -- make clean compile
+
+bear: clean
+	@touch .ccls-root
+	@$(BEAR) -- make compile
diff --git a/2022/day03/README.org b/2022/day03/README.org
new file mode 100644
index 0000000..0b50ed0
--- /dev/null
+++ b/2022/day03/README.org
@@ -0,0 +1,121 @@
+** --- Day 3: Rucksack Reorganization ---
+One Elf has the important job of loading all of the
+[[https://en.wikipedia.org/wiki/Rucksack][rucksacks]] with supplies for
+the jungle journey. Unfortunately, that Elf didn't quite follow the
+packing instructions, and so a few items now need to be rearranged.
+
+Each rucksack has two large /compartments/. All items of a given type
+are meant to go into exactly one of the two compartments. The Elf that
+did the packing failed to follow this rule for exactly one item type per
+rucksack.
+
+The Elves have made a list of all of the items currently in each
+rucksack (your puzzle input), but they need your help finding the
+errors. Every item type is identified by a single lowercase or uppercase
+letter (that is, =a= and =A= refer to different types of items).
+
+The list of items for each rucksack is given as characters all on a
+single line. A given rucksack always has the same number of items in
+each of its two compartments, so the first half of the characters
+represent items in the first compartment, while the second half of the
+characters represent items in the second compartment.
+
+For example, suppose you have the following list of contents from six
+rucksacks:
+
+#+begin_example
+vJrwpWtwJgWrhcsFMMfFFhFp
+jqHRNqRjqzjGDLGLrsFMfFZSrLrFZsSL
+PmmdzqPrVvPwwTWBwg
+wMqvLMZHhHMvwLHjbvcjnnSBnvTQFn
+ttgJtRGJQctTZtZT
+CrZsJsPPZsGzwwsLwLmpwMDw
+#+end_example
+
+- The first rucksack contains the items =vJrwpWtwJgWrhcsFMMfFFhFp=,
+  which means its first compartment contains the items =vJrwpWtwJgWr=,
+  while the second compartment contains the items =hcsFMMfFFhFp=. The
+  only item type that appears in both compartments is lowercase =p=.
+- The second rucksack's compartments contain =jqHRNqRjqzjGDLGL= and
+  =rsFMfFZSrLrFZsSL=. The only item type that appears in both
+  compartments is uppercase =L=.
+- The third rucksack's compartments contain =PmmdzqPrV= and =vPwwTWBwg=;
+  the only common item type is uppercase =P=.
+- The fourth rucksack's compartments only share item type =v=.
+- The fifth rucksack's compartments only share item type =t=.
+- The sixth rucksack's compartments only share item type =s=.
+
+To help prioritize item rearrangement, every item type can be converted
+to a /priority/:
+
+- Lowercase item types =a= through =z= have priorities 1 through 26.
+- Uppercase item types =A= through =Z= have priorities 27 through 52.
+
+In the above example, the priority of the item type that appears in both
+compartments of each rucksack is 16 (=p=), 38 (=L=), 42 (=P=), 22 (=v=),
+20 (=t=), and 19 (=s=); the sum of these is =157=.
+
+Find the item type that appears in both compartments of each rucksack.
+/What is the sum of the priorities of those item types?/
+
+Your puzzle answer was =7878=.
+
+The first half of this puzzle is complete! It provides one gold star: *
+
+** --- Part Two ---
+As you finish identifying the misplaced items, the Elves come to you
+with another issue.
+
+For safety, the Elves are divided into groups of three. Every Elf
+carries a badge that identifies their group. For efficiency, within each
+group of three Elves, the badge is the /only item type carried by all
+three Elves/. That is, if a group's badge is item type =B=, then all
+three Elves will have item type =B= somewhere in their rucksack, and at
+most two of the Elves will be carrying any other item type.
+
+The problem is that someone forgot to put this year's updated
+authenticity sticker on the badges. All of the badges need to be pulled
+out of the rucksacks so the new authenticity stickers can be attached.
+
+Additionally, nobody wrote down which item type corresponds to each
+group's badges. The only way to tell which item type is the right one is
+by finding the one item type that is /common between all three Elves/ in
+each group.
+
+Every set of three lines in your list corresponds to a single group, but
+each group can have a different badge item type. So, in the above
+example, the first group's rucksacks are the first three lines:
+
+#+begin_example
+vJrwpWtwJgWrhcsFMMfFFhFp
+jqHRNqRjqzjGDLGLrsFMfFZSrLrFZsSL
+PmmdzqPrVvPwwTWBwg
+#+end_example
+
+And the second group's rucksacks are the next three lines:
+
+#+begin_example
+wMqvLMZHhHMvwLHjbvcjnnSBnvTQFn
+ttgJtRGJQctTZtZT
+CrZsJsPPZsGzwwsLwLmpwMDw
+#+end_example
+
+In the first group, the only item type that appears in all three
+rucksacks is lowercase =r=; this must be their badges. In the second
+group, their badge item type must be =Z=.
+
+Priorities for these items must still be found to organize the sticker
+attachment efforts: here, they are 18 (=r=) for the first group and 52
+(=Z=) for the second group. The sum of these is =70=.
+
+Find the item type that corresponds to the badges of each three-Elf
+group. /What is the sum of the priorities of those item types?/
+
+Answer:
+
+Although it hasn't changed, you can still [[file:3/input][get your
+puzzle input]].
+
+You can also [Shareon
+[[https://twitter.com/intent/tweet?text=I%27ve+completed+Part+One+of+%22Rucksack+Reorganization%22+%2D+Day+3+%2D+Advent+of+Code+2022&url=https%3A%2F%2Fadventofcode%2Ecom%2F2022%2Fday%2F3&related=ericwastl&hashtags=AdventOfCode][Twitter]]
+[[javascript:void(0);][Mastodon]]] this puzzle.
diff --git a/2022/day03/aoc.bash b/2022/day03/aoc.bash
new file mode 100755
index 0000000..0fdf1f1
--- /dev/null
+++ b/2022/day03/aoc.bash
@@ -0,0 +1,70 @@
+#!/usr/bin/env bash
+#
+# aoc.bash: Advent of Code 2022, day 2
+#
+# Copyright (C) 2022 Bruno Raoult ("br")
+# Licensed under the GNU General Public License v3.0 or later.
+# Some rights reserved. See COPYING.
+#
+# You should have received a copy of the GNU General Public License along with this
+# program. If not, see <https://www.gnu.org/licenses/gpl-3.0-standalone.html>.
+#
+# SPDX-License-Identifier: GPL-3.0-or-later <https://spdx.org/licenses/GPL-3.0-or-later.html>
+
+. common.bash
+
+export LANG=C
+declare -a tot=(1 2)
+
+# get priority value for an item
+# $1: character
+prio() {
+    local -n _val="$1"
+    local _char="$2"
+
+    printf -v _val "%d" "'$_char"
+    if [[ $_char > "Z" ]]; then                   # a-z
+        ((_val += (1 - 97) ))
+    else                                          # A-Z
+        ((_val += (27 - 65) ))
+    fi
+}
+
+parse() {
+    local input half1 half2 result=""
+    local -i len half i j=1 prio part1=0 line=1
+
+    while read -r input; do
+        (( len = ${#input}, half = len/2 ))
+        half1="${input:0:half}"
+        half2="${input:half}"
+        result=""
+
+        #printf "[%d] l=%d h=%d [%s / %s]\n" "$line" "$len" "$half" "$half1" "$half2"
+
+        #c="${half1//[^${half2}]}"
+        #prio prio "${c:0:1}"
+        #(( part1 += prio ))
+
+        for ((i = 0; i < half; ++i)); do
+            c=${half1:$i:1}
+            if [[ $result != *$c* && $half2 == *$c* ]]; then
+                echo "found $c"
+                result=$result$c
+                prio prio "${c:0:1}"
+                (( part1 += prio ))
+                #printf "%d prio(%c)=%d tot=%d\n" "$line" "$c" "$prio" "$part1"
+            fi
+        done
+        ((j++, line++))
+        echo
+    done
+    echo "result=$part1"
+}
+
+solve() {
+    res="${tot[$1]}"
+}
+
+main "$@"
+exit 0
diff --git a/2022/day03/common.bash b/2022/day03/common.bash
new file mode 100755
index 0000000..c220552
--- /dev/null
+++ b/2022/day03/common.bash
@@ -0,0 +1,67 @@
+#!/usr/bin/env bash
+#
+# common.bash: Advent of Code 2022, common bash functions
+#
+# Copyright (C) 2022 Bruno Raoult ("br")
+# Licensed under the GNU General Public License v3.0 or later.
+# Some rights reserved. See COPYING.
+#
+# You should have received a copy of the GNU General Public License along with this
+# program. If not, see <https://www.gnu.org/licenses/gpl-3.0-standalone.html>.
+#
+# SPDX-License-Identifier: GPL-3.0-or-later <https://spdx.org/licenses/GPL-3.0-or-later.html>
+
+# shellcheck disable=2034
+export cmdname=${0##*/}
+export debug=0
+export res
+
+shopt -s extglob
+set -o noglob
+
+usage() {
+    printf "usage: %s [-d DEBUG] [-p PART]\n" "$cmdname"
+    exit 1
+}
+
+checkargs() {
+    local part=1
+    while getopts p:d: todo; do
+        case "$todo" in
+            d)
+                if [[ "$OPTARG" =~ ^[[:digit:]+]$ ]]; then
+                    debug="$OPTARG"
+                else
+                    printf "%s: illegal [%s] debug level.\n" "$CMD" "$OPTARG"
+                    exit 1
+                fi
+                ;;
+            p)
+                if [[ "$OPTARG" =~ ^[12]$ ]]; then
+                    part="$OPTARG"
+                else
+                    printf "%s: illegal [%s] part.\n" "$CMD" "$OPTARG"
+                    exit 1
+                fi
+                ;;
+            *)
+                usage
+                ;;
+        esac
+    done
+    # Now check remaining argument (backup directory)
+    shift $((OPTIND - 1))
+
+    (( $# > 1 )) && usage
+    return "$part"
+}
+
+main() {
+    local -i part
+
+    checkargs "$@"
+    part=$?
+    parse "$part"
+    solve "$part"
+    printf "%s: res=%s\n" "$cmdname" "$res"
+}
diff --git a/2022/day03/input/example.txt b/2022/day03/input/example.txt
new file mode 100644
index 0000000..f17e726
--- /dev/null
+++ b/2022/day03/input/example.txt
@@ -0,0 +1,6 @@
+vJrwpWtwJgWrhcsFMMfFFhFp
+jqHRNqRjqzjGDLGLrsFMfFZSrLrFZsSL
+PmmdzqPrVvPwwTWBwg
+wMqvLMZHhHMvwLHjbvcjnnSBnvTQFn
+ttgJtRGJQctTZtZT
+CrZsJsPPZsGzwwsLwLmpwMDw
diff --git a/2022/day03/input/input.txt b/2022/day03/input/input.txt
new file mode 100644
index 0000000..46aefe5
--- /dev/null
+++ b/2022/day03/input/input.txt
@@ -0,0 +1,300 @@
+ZNNvFWHqLNPZHHqPTHHnTGBhrrpjvmwfMmpfpjBjwpmw
+sbdzQgzgssgbglRtmjlwhjBlfrSrMt
+zgsCRzJbsdRVQCDbcgLGWWLnZNGVLLZMNZnq
+tvHhRtZGMvMHvfsrBBCTRbwbccRc
+qznnlpzzDppWlDpQpCrcrwnBNwTZnBTZrn
+PdVZJJqVZdllDPFtMjMgLjGMHvSgMF
+csbhhVDDvzlVDcbccGGvfRjDHCjNLRHRCLfmnZfR
+dFrStSTTmrrrHVfV
+MMgQMMTMVTdgWtwTPwSgWSgGbbppJzlplvhBlPbzhlhbzG
+FDJSTtSGhpPFDmFTZDpTFPmCBBrHqsCBhgBlqqrqrlRrHH
+dQwMtfdzVwWfwctwnfnQCHllzRrsNzrrgNlCgqsr
+fLfQnVjfwQfMdfvfnVvWDvtJPFGDpvZGbZpmbSPP
+TzzCrJcDrTDdLDCJDvGNPCFqlZWlvNvWpq
+RRHfjsQBFsjgjBQsWqGpNvZQqQlPPQPN
+VnHBnRVssnnjsSfBwbMSrrbTwJTcwSDF
+HJCgHCCFFFVGJWTlbqDdlqTDDpgl
+cZccSmLrfZcrmmzSQftdpDtTHdbQTDMQ
+NZZccrrBwZRPNNzmcLSSjJhGhVWCnsFnHBjGChsJ
+qwwwJHTHqdFDtZBFPfFBZFzM
+gVRcLnnWVgggnnnQgVWWNZtZrBfLBzZzBrMPPrZvPv
+GQgQSVRtsVnNRGSCdpmwspmbmDpHmhwd
+bhNgNfgwpbLMhCZMGQBmDm
+FrcHrSllcqcFFMGLBDQlMDTGlT
+FVSddRSJRjLwbjJPJw
+wzhhrTwwTrSsdHQjjSHnBjQj
+gRDCmVgRgMvtMfVMRBBBhWCHQQHGJHZJQZ
+NtgVgttVbMNmvsNlpcrLhLTNPw
+MCgjsfnscgjjgnGgJHHqHDgdHbGr
+QSSmRFPpRtPFQLQRmPzvBzzzDWqrqWWHJGGNrJJbdtVWHJDV
+BdSFdLQzRFlSLmQplffwncfscChhcsMj
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+mrnqlqMqBlSSLnBTLBwmHPPWhPPHtFRPWzwt
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+LFtdjHjLjLqHqstLTjFLFqNMnMhhZdDDNMVbWdDDbhnZ
+CrBpBGnzrzmczcllrphCZZWJMDWRbbZNMDMR
+GwgvzpzvrcmBrnfHjTgqTsgHjF
+rMPPZcplCZlZPwtSwhtBwCQQzB
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+bSJWhWJCbGGWJPStWTgRQwzDjgQQjsDW
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