fetch-all: add possible local branch creation (still only echo)
This commit is contained in:
@@ -1,3 +1,46 @@
|
||||
#!/usr/bin/env bash
|
||||
|
||||
git remote | xargs -n 1 git fetch -a
|
||||
origin=origin
|
||||
|
||||
declare -a remotes local
|
||||
|
||||
readarray -t remotes < <(git remote)
|
||||
declare -A aremotes alocal_b
|
||||
|
||||
# fetch all remotes
|
||||
for remote in "${remotes[@]}"; do
|
||||
aremotes["$remote"]=1
|
||||
echo doing git fetch -a "$remote"
|
||||
done
|
||||
|
||||
# get local branches
|
||||
readarray -t local_b < <(git for-each-ref --format='%(refname:short)' refs/heads/)
|
||||
|
||||
# build local ref array
|
||||
for ref in "${local_b[@]}"; do
|
||||
alocal_b[$ref]=1
|
||||
done
|
||||
|
||||
|
||||
readarray -t orig_b < <(git for-each-ref --format='%(refname:short)' \
|
||||
refs/remotes/"$origin"/)
|
||||
|
||||
declare -p remotes
|
||||
#declare -p aremotes
|
||||
declare -p local_b orig_b
|
||||
|
||||
# find-out missing local branches
|
||||
for remote_b in "${orig_b[@]}"; do
|
||||
short=${remote_b#"$origin"/};
|
||||
echo "$remote_b -> $short ${alocal_b[$short]}"
|
||||
if ! [[ -v alocal_b[$short] ]]; then
|
||||
echo git switch -t "$remote_b"
|
||||
fi
|
||||
done
|
||||
|
||||
|
||||
|
||||
|
||||
|
||||
|
||||
#git remote | xargs -n 1 git fetch -a
|
||||
|
Reference in New Issue
Block a user