73 lines
2.1 KiB
Bash
Executable File
73 lines
2.1 KiB
Bash
Executable File
#!/usr/bin/env bash
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#
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# aoc.bash: Advent of Code 2022, day 6
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#
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# Copyright (C) 2022 Bruno Raoult ("br")
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# Licensed under the GNU General Public License v3.0 or later.
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# Some rights reserved. See COPYING.
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#
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# You should have received a copy of the GNU General Public License along with this
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# program. If not, see <https://www.gnu.org/licenses/gpl-3.0-standalone.html>.
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#
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# SPDX-License-Identifier: GPL-3.0-or-later <https://spdx.org/licenses/GPL-3.0-or-later.html>
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. common.bash
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declare -a stacks=() rules=()
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parse() {
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local -i _queue _state=1
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local _input
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local -a _parse
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local cur=""
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local -i lcur=0 i
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read -r _input
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len=${#_input}
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lcur=0
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for (( i = 0; i < len - 4; ++i )); do
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echo
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nextc=${_input:i:1} # get next char
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printf "next=%s cur=%s lcur=%d\n" "$nextc" "$cur" "$lcur"
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for ((j = 0; j < lcur; ++j)); do # compare with previous ones
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printf "compare %s with %d:%s\n" "$nextc" "$j" "${cur:j:1}"
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if [[ $nextc == "${cur:j:1}" ]]; then
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cur=${cur:j+1}$nextc
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(( lcur = lcur - (j + 1) + 1))
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printf "\t-> equal cur=%d:%s" "$lcur" "$cur"
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continue 2
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fi
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done
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cur+=$nextc
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((lcur++))
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((lcur == 4)) && break
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done
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echo "$cur" $((i + 1))
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}
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solve() {
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local -i _part="$1" _i=0 _j=0 _nb _from _to
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local -a _rule
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for ((; _i < ${#rules[@]}; ++_i )); do
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read -ra _rule <<< "${rules[$_i]}"
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(( _nb = _rule[0], _from = _rule[1] - 1, _to = _rule[2] - 1 ))
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if ((_part == 1)); then
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# move elements one by one
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for ((_j = 0; _j < _nb; ++_j)); do
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stacks[$_to]="${stacks[$_from]:0:1}${stacks[$_to]}"
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stacks[$_from]=${stacks[$_from]:1}
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done
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else
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# move elements by block
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stacks[$_to]="${stacks[$_from]:0:_nb}${stacks[$_to]}"
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stacks[$_from]=${stacks[$_from]:_nb}
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fi
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done
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printf -v res "%c" "${stacks[@]}"
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}
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main "$@"
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exit 0
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