/* aoc-c.c: Advent of Code 2021, day 20 parts 1 & 2 * * Copyright (C) 2022 Bruno Raoult ("br") * Licensed under the GNU General Public License v3.0 or later. * Some rights reserved. See COPYING. * * You should have received a copy of the GNU General Public License along with this * program. If not, see . * * SPDX-License-Identifier: GPL-3.0-or-later */ #include #include #include #include #include #include "pool.h" #include "debug.h" #include "bits.h" #include "list.h" #define ALGOLEN 512 static char algorithm[ALGOLEN]; /* input algorithm */ static int universe_size = 0; /* universe width/height */ static char **universe[2]; static int left, right; /* universe current borders */ static int current = 0; /* active universe */ #ifdef DEBUG /* print current universe */ static void print_data(int step) { for (int i = 0; i < algolen; ++i) log(5, "%c", algo[i]? '#': '.'); log(5, "\n"); log_f(1, "step %d, current=%d\n", step, current); for (int i = left; i < right; ++i) { for (int j = left; j < right; ++j) log(1, "%c", universe[current][i][j]? '#': '.'); log(1, "\n"); } } #endif /* make one step */ static inline int count() { int res = 0; for (int i = left; i < right; ++i) for (int j = left; j < right; ++j) res += universe[current][i][j]; return res; } /* make one step */ static inline void step() { int index; left--; right++; for (int j = left; j < right; ++j) { for (int i = left; i < right; ++i) { index = universe[current][i-1][j-1] << 8 | universe[current][i-1][j ] << 7 | universe[current][i-1][j+1] << 6 | universe[current][i ][j-1] << 5 | universe[current][i ][j ] << 4 | universe[current][i ][j+1] << 3 | universe[current][i+1][j-1] << 2 | universe[current][i+1][j ] << 1 | universe[current][i+1][j+1] << 0; universe[!current][i][j] = algorithm[index]; } } current = !current; } /* read input */ static int read_data(int steps) { int i = 0, cur = 0; size_t alloc = 0; ssize_t buflen; char *buf = NULL; buflen = getline(&buf, &alloc, stdin) - 1; for (int i = 0; i < buflen; ++i) algorithm[i] = buf[i] == '#'; /* We consider input will be a square, first line determines * the width */ getline(&buf, &alloc, stdin); /* skip second line */ buflen = getline(&buf, &alloc, stdin) - 1; /* universe grows by 1 on 4 side (= +2 width and +2 height), * and we need also to keep one extra border for calculation. */ universe_size = buflen + 2 * steps + 2; left = steps + 1; right = universe_size - left; universe[0] = malloc(universe_size * sizeof(char *)); universe[1] = malloc(universe_size * sizeof(char *)); for (i = 0; i < universe_size; ++i) { universe[0][i] = calloc(universe_size, sizeof(char)); universe[1][i] = calloc(universe_size, sizeof(char)); } /* they got me on this one, different from given example ;-) * We need to fill the odd universe with '1' if algorithm[0] is 1 * (whole universe becomes lit). * It would be better to consider also the case algorithm[511] is 1, * and algorithm[0] is 0 (we could only count after odd steps). */ if (*algorithm) { for (i = 0; i < universe_size; ++i) memset(universe[1][i], 1, universe_size); if (algorithm[ALGOLEN - 1]) { log(0, "cannot display infinity ;-)\n"); return 0; } } do { for (int i = 0; i < buflen; ++i) universe[0][cur + left][i + left] = buf[i] == '#'; cur++; buflen = getline(&buf, &alloc, stdin) - 1; } while (cur < universe_size && buflen > 0); free(buf); return 1; } static int doit(int iter) { for (int i = 0; i < iter; ++i) step(); return count(); } static int usage(char *prg) { fprintf(stderr, "Usage: %s [-d debug_level] [-p part]\n", prg); return 1; } int main(int ac, char **av) { int opt, part = 1; while ((opt = getopt(ac, av, "d:p:")) != -1) { switch (opt) { case 'd': debug_level_set(atoi(optarg)); break; case 'p': /* 1 or 2 */ part = atoi(optarg); if (part < 1 || part > 2) return usage(*av); break; default: return usage(*av); } } if (optind < ac) return usage(*av); int iter = part == 1? 2: 50; if (read_data(iter)) printf("%s : res=%d\n", *av, doit(iter)); for (int i = 0; i < universe_size; ++i) { free(universe[0][i]); free(universe[1][i]); } free(universe[0]); free(universe[1]); exit(0); }