2022 day 13 part 1 (C)

2022/day13/README.org

@@ -141,3 +141,57 @@ sum of these indices is =13=.
 
 Determine which pairs of packets are already in the right order. /What
 is the sum of the indices of those pairs?/
+
+Your puzzle answer was =5843=.
+
+The first half of this puzzle is complete! It provides one gold star: *
+
+** --- Part Two ---
+Now, you just need to put /all/ of the packets in the right order.
+Disregard the blank lines in your list of received packets.
+
+The distress signal protocol also requires that you include two
+additional /divider packets/:
+
+#+begin_example
+[[2]]
+[[6]]
+#+end_example
+
+Using the same rules as before, organize all packets - the ones in your
+list of received packets as well as the two divider packets - into the
+correct order.
+
+For the example above, the result of putting the packets in the correct
+order is:
+
+#+begin_example
+[]
+[[]]
+[[[]]]
+[1,1,3,1,1]
+[1,1,5,1,1]
+[[1],[2,3,4]]
+[1,[2,[3,[4,[5,6,0]]]],8,9]
+[1,[2,[3,[4,[5,6,7]]]],8,9]
+[[1],4]
+[[2]]
+[3]
+[[4,4],4,4]
+[[4,4],4,4,4]
+[[6]]
+[7,7,7]
+[7,7,7,7]
+[[8,7,6]]
+[9]
+#+end_example
+
+Afterward, locate the divider packets. To find the /decoder key/ for
+this distress signal, you need to determine the indices of the two
+divider packets and multiply them together. (The first packet is at
+index 1, the second packet is at index 2, and so on.) In this example,
+the divider packets are /10th/ and /14th/, and so the decoder key is
+=140=.
+
+Organize all of the packets into the correct order. /What is the decoder
+key for the distress signal?/