2022 day 6: C (parts 1 and 2)
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@@ -117,7 +117,15 @@ aoc.bash: res=1658
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time: 0:00.06 real, 0.06 user, 0.00 sys
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context-switch: 1+1, page-faults: 0+266
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aoc-c: res=1658
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time: 0:00.00 real, 0.00 user, 0.00 sys
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context-switch: 0+1, page-faults: 0+87
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+++++++++++++++++ part 2
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aoc.bash: res=2260
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time: 0:00.09 real, 0.09 user, 0.00 sys
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context-switch: 1+1, page-faults: 0+265
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aoc-c: res=2260
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time: 0:00.00 real, 0.00 user, 0.00 sys
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context-switch: 0+1, page-faults: 0+87
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60
2022/day06/aoc-c.c
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60
2022/day06/aoc-c.c
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@@ -0,0 +1,60 @@
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/* aoc-c.c: Advent of Code 2022, day 6
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*
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* Copyright (C) 2022 Bruno Raoult ("br")
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* Licensed under the GNU General Public License v3.0 or later.
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* Some rights reserved. See COPYING.
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*
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* You should have received a copy of the GNU General Public License along with this
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* program. If not, see <https://www.gnu.org/licenses/gpl-3.0-standalone.html>.
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*
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* SPDX-License-Identifier: GPL-3.0-or-later <https://spdx.org/licenses/GPL-3.0-or-later.html>
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*/
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#include <stdio.h>
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#include <stdlib.h>
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#include <string.h>
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#include "br.h"
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#include "aoc.h"
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struct msg {
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char *data;
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size_t len;
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};
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static struct msg *parse(struct msg *msg)
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{
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size_t alloc = 0;
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msg->data=NULL;
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msg->len = getline(&msg->data, &alloc, stdin);
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msg->data[--msg->len] = 0;
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return msg;
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}
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static int solve(struct msg *msg, int marklen)
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{
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char *pcur = msg->data, *pnext = pcur;
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int len = msg->len, lmark = 0;
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for (; pnext < msg->data + len && lmark < marklen; lmark = ++pnext - pcur) {
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for (int j = 0; j < lmark; ++j) { /* compare with prev marker chars */
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if (*(pcur+j) == *pnext) { /* check new char with cur marker */
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pcur += j + 1; /* move marker to after dup char */
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goto nextchar;
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}
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}
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nextchar: ;
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}
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return pnext - msg->data;
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}
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int main(int ac, char **av)
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{
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int part = parseargs(ac, av);
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struct msg msg;
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printf("%s: res=%d\n", *av, solve(parse(&msg), part == 1? 4:14));
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free(msg.data);
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exit(0);
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}
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@@ -32,7 +32,7 @@ solve() {
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for ((j = 0; j < lcur; ++j)); do # compare with previous ones
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if [[ $next == "${cur:j:1}" ]]; then # duplicate
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cur="${cur:j+1}$next" # keep str after dup + new char
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(( lcur = lcur - j ))
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(( lcur -= j ))
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continue 2
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fi
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done
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