2022 day 6: C (parts 1 and 2)
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@@ -32,7 +32,7 @@ solve() {
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for ((j = 0; j < lcur; ++j)); do # compare with previous ones
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if [[ $next == "${cur:j:1}" ]]; then # duplicate
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cur="${cur:j+1}$next" # keep str after dup + new char
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(( lcur = lcur - j ))
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(( lcur -= j ))
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continue 2
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fi
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done
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