From 295f032d6ac19d2da25275d5920f62b5b3289998 Mon Sep 17 00:00:00 2001 From: Bruno Raoult Date: Wed, 15 Dec 2021 16:03:01 +0100 Subject: [PATCH] day 14 init --- 2021/day14/EXAMPLE.txt | 18 ++++++++ 2021/day14/INPUT.txt | 102 +++++++++++++++++++++++++++++++++++++++++ 2021/day14/Makefile | 58 +++++++++++++++++++++++ 2021/day14/README.txt | 52 +++++++++++++++++++++ 4 files changed, 230 insertions(+) create mode 100644 2021/day14/EXAMPLE.txt create mode 100644 2021/day14/INPUT.txt create mode 100644 2021/day14/Makefile create mode 100644 2021/day14/README.txt diff --git a/2021/day14/EXAMPLE.txt b/2021/day14/EXAMPLE.txt new file mode 100644 index 0000000..b5594dd --- /dev/null +++ b/2021/day14/EXAMPLE.txt @@ -0,0 +1,18 @@ +NNCB + +CH -> B +HH -> N +CB -> H +NH -> C +HB -> C +HC -> B +HN -> C +NN -> C +BH -> H +NC -> B +NB -> B +BN -> B +BB -> N +BC -> B +CC -> N +CN -> C diff --git a/2021/day14/INPUT.txt b/2021/day14/INPUT.txt new file mode 100644 index 0000000..5074877 --- /dev/null +++ b/2021/day14/INPUT.txt @@ -0,0 +1,102 @@ +SCVHKHVSHPVCNBKBPVHV + +SB -> B +HH -> P +VF -> N +BS -> S +NC -> C +BF -> H +BN -> H +SP -> H +BK -> H +FF -> N +VN -> B +FN -> C +FS -> S +PP -> F +ON -> H +FV -> F +KO -> F +PK -> H +VB -> S +HS -> B +NV -> O +PN -> S +VH -> B +OS -> P +BP -> H +OV -> B +HK -> S +NN -> K +SV -> C +PB -> F +SK -> F +FB -> S +NB -> K +HF -> P +FK -> K +KV -> P +PV -> F +BC -> S +FO -> N +HC -> F +CP -> B +KK -> F +PC -> S +HN -> O +SH -> H +CK -> P +CO -> F +HP -> K +PS -> C +KP -> F +OF -> K +KS -> F +NO -> V +CB -> K +NF -> N +SF -> F +SC -> P +FC -> V +BV -> B +SS -> O +KC -> K +FH -> C +OP -> C +CF -> K +VO -> V +VK -> H +KH -> O +NP -> V +NH -> O +NS -> V +BH -> C +CH -> S +CC -> F +CS -> P +SN -> F +BO -> S +NK -> S +OO -> P +VV -> F +FP -> V +OK -> C +SO -> H +KN -> P +HO -> O +PO -> H +VS -> N +PF -> N +CV -> F +BB -> H +VC -> H +HV -> B +CN -> S +OH -> K +KF -> K +HB -> S +OC -> H +KB -> P +OB -> C +VP -> C +PH -> K diff --git a/2021/day14/Makefile b/2021/day14/Makefile new file mode 100644 index 0000000..44a0866 --- /dev/null +++ b/2021/day14/Makefile @@ -0,0 +1,58 @@ +# AOC daily Makefile - GNU make only. +# +# Copyright (C) 2021 Bruno Raoult ("br") +# Licensed under the GNU General Public License v3.0 or later. +# Some rights reserved. See COPYING. +# +# You should have received a copy of the GNU General Public License along with this +# program. If not, see . +# +# SPDX-License-Identifier: GPL-3.0-or-later +# + +INPUT := INPUT.txt +SHELL := /bin/bash + +CC := gcc + +LIB := aoc_$(shell uname -m) +INCDIR := ../include +LIBDIR := ../lib +LDFLAGS := -L$(LIBDIR) +LDLIB := -l$(LIB) + +export LD_LIBRARY_PATH = $(LIBDIR) + +CFLAGS += -std=gnu99 +#CFLAGS += -O2 +CFLAGS += -g +CFLAGS += -Wall +CFLAGS += -Wextra +CFLAGS += -march=native +CFLAGS += -Wmissing-declarations +CFLAGS += -Wno-unused-result + +CFLAGS += -DDEBUG_DEBUG # activate general debug (debug.c) +CFLAGS += -DDEBUG_POOL # memory pools management + +TIME := \time -f "\ttime: %E real, %U user, %S sys\n\tcontext-switch:\t%c+%w, page-faults: %F+%R\n" +export PATH := .:$(PATH) + +.PHONY: clean all compile ex1 ex2 + +all: ex1 ex2 + +compile: aoc-c + +ex1: aoc-c + @$(TIME) aoc-c -p 1 < $(INPUT) + +ex2: aoc-c + @$(TIME) aoc-c -p 2 < $(INPUT) + +clean: + @rm -f aoc-c core* + +.c: + @echo compiling $< + @$(CC) $(CFLAGS) $(LDFLAGS) -I $(INCDIR) $< $(LDLIB) -o $@ diff --git a/2021/day14/README.txt b/2021/day14/README.txt new file mode 100644 index 0000000..cc2f0a2 --- /dev/null +++ b/2021/day14/README.txt @@ -0,0 +1,52 @@ +--- Day 14: Extended Polymerization --- + +The incredible pressures at this depth are starting to put a strain on your submarine. The submarine has polymerization equipment that would produce suitable materials to reinforce the submarine, and the nearby volcanically-active caves should even have the necessary input elements in sufficient quantities. + +The submarine manual contains instructions for finding the optimal polymer formula; specifically, it offers a polymer template and a list of pair insertion rules (your puzzle input). You just need to work out what polymer would result after repeating the pair insertion process a few times. + +For example: + +NNCB + +CH -> B +HH -> N +CB -> H +NH -> C +HB -> C +HC -> B +HN -> C +NN -> C +BH -> H +NC -> B +NB -> B +BN -> B +BB -> N +BC -> B +CC -> N +CN -> C + +The first line is the polymer template - this is the starting point of the process. + +The following section defines the pair insertion rules. A rule like AB -> C means that when elements A and B are immediately adjacent, element C should be inserted between them. These insertions all happen simultaneously. + +So, starting with the polymer template NNCB, the first step simultaneously considers all three pairs: + + The first pair (NN) matches the rule NN -> C, so element C is inserted between the first N and the second N. + The second pair (NC) matches the rule NC -> B, so element B is inserted between the N and the C. + The third pair (CB) matches the rule CB -> H, so element H is inserted between the C and the B. + +Note that these pairs overlap: the second element of one pair is the first element of the next pair. Also, because all pairs are considered simultaneously, inserted elements are not considered to be part of a pair until the next step. + +After the first step of this process, the polymer becomes NCNBCHB. + +Here are the results of a few steps using the above rules: + +Template: NNCB +After step 1: NCNBCHB +After step 2: NBCCNBBBCBHCB +After step 3: NBBBCNCCNBBNBNBBCHBHHBCHB +After step 4: NBBNBNBBCCNBCNCCNBBNBBNBBBNBBNBBCBHCBHHNHCBBCBHCB + +This polymer grows quickly. After step 5, it has length 97; After step 10, it has length 3073. After step 10, B occurs 1749 times, C occurs 298 times, H occurs 161 times, and N occurs 865 times; taking the quantity of the most common element (B, 1749) and subtracting the quantity of the least common element (H, 161) produces 1749 - 161 = 1588. + +Apply 10 steps of pair insertion to the polymer template and find the most and least common elements in the result. What do you get if you take the quantity of the most common element and subtract the quantity of the least common element?