count matches w/ string manipulation: ~75% gain, 85-90% gain from V1
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8
OUTPUT
8
OUTPUT
@@ -443,3 +443,11 @@ ex1.bash : res=285
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ex2.bash : res=412
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time: 0:03.37 real, 3.34 user, 0.03 sys
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context-switch: 19+1, page-faults: 0+11909
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=========================================
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================= day20 =================
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=========================================
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ex1.bash : res=5966506063747
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time: 0:00.54 real, 0.53 user, 0.00 sys
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context-switch: 1+1, page-faults: 0+223
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@@ -20,7 +20,7 @@ ex1:
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@#$(TIME) ex1-c 2020 < $(INPUT) 2>&1
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ex2:
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@$(TIME) ex2.bash < $(INPUT) 2>&1
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@#$(TIME) ex2.bash < $(INPUT) 2>&1
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@#$(TIME) ex1-c 30000000 < $(INPUT) 2>&1
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clean:
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4
day20/OUTPUT
Normal file
4
day20/OUTPUT
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@@ -0,0 +1,4 @@
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ex1.bash : res=5966506063747
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time: 0:00.54 real, 0.53 user, 0.00 sys
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context-switch: 1+1, page-faults: 0+223
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@@ -54,18 +54,21 @@ for key in "${!nums[@]}"; do
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done
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ALL=("${T[@]}" "${R[@]}" "${B[@]}" "${L[@]}" "${RT[@]}" "${RR[@]}" "${RB[@]}" "${RL[@]}")
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ALL="${T[@]} ${R[@]} ${B[@]} ${L[@]} ${RT[@]} ${RR[@]} ${RB[@]} ${RL[@]}"
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ALLSIZE=${#ALL}
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declare -i res=1 count
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for ((i=0; i<${#nums[@]}; ++i)); do
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count=0
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for t in ${T[$i]} ${R[$i]} ${B[$i]} ${L[$i]}; do
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for s in "${ALL[@]}"; do
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[[ $t == "$s" ]] && ((count++))
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# https://stackoverflow.com/questions/26212889/bash-counting-substrings-in-a-string/50601141#50601141
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S=${ALL//$t}
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# 10 is line size
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((count += (ALLSIZE-${#S})/10))
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done
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done
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((count ==6)) && ((res*=${nums[$i]}))
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# 6 is 4 for itself, + 2 for other matching
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((count == 6)) && ((res*=${nums[$i]}))
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done
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printf "%s : res=%d\n" "$CMD" "$res"
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